Question

Find the co-ordinates and centre of the circle. x2+y2-6x+14y+33=0​

Answer 1

Answer:

Centre of first circle

x2+y2+16x−14y−1=0.is(−g,−f)⇒(−8,7)→PForIICircle:Centre→(2,−5)→QEquationofcirclewithP&Qasdiametricendpoints:Centre→(2−8+2,27−5)⇒(−3,1).radius=21(2+8)2+(−5−7)2=21100+144=2244.⇒(x+3)2+(y−1)2=4244⇒(x+3)2+(y−1)2=61

Step-by-step explanation: