Question

Find the co-ordinates of a centroid of a triangle whose vertices are (3,–5), (–7,4) and (10,–2).

Answer 1

Coordinate geometry is the branch of mathematics which deals with the position of an object lying in a plane.

Each  point in cartesian plane has two coordinates X coordinate and Y coordinate.
The X co-ordinate is called the abscissa.
The Y co-ordinate is called the ordinate.

Coordinates X and Y taken together are called coordinates of a point. (x,y) is called an ordered pair.

SOLUTION:

We know that the coordinates of the centroid of a triangle whose vertices  are (x1,y1), (x2,y2), (x3,y3) are:

[(x1+x2+x3)/3 , (y1+y2+y3)/3]

GIVEN:
Here, (x1= 3 ,y1= -5), (x2= -7,y2= 4), (x3= 10,y3= -2)

The coordinates of the centroid of a triangle  are= [(3+(-7)+10)/3, (-5 +4+(-2)/3]
= [6/3 , -3/3]

= 2,-1

Hence, the  co-ordinates  of a centroid  of a triangle is (2, -1).

HOPE THIS WILL HELP YOU...

Answer 2

hay!!

dear user

In the given equation we know that

x1=3,y1=-5. x2=-7,y2=4. x3=10,y3=-2

Then

[(3-7+10/3),(5+4-2/3)]
(6/3,-3/3)
2,-1

I hope it's help you