find the co-ordinates of a point on Y-axis which is equidistant from M(-5,-2)&N(3,2)
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Answer:
let point be A and its coordinates be (0,y)
AN = AM
√(3-0)²+(2-y)² = √(-5-0)²+(-2-y)²
9+4+y²-4y = 25+y²+4+4y
8y+16 = 0
8y = -16
y = -2
coordinates will be (0,-2)
Step-by-step explanation:
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