Question

Find the co ordinates of a point whose abscissa is 10 and its distance from the point (2 -3) is 10 units.​

Answer 1

Step-by-step explanation:

10 = √(10-2)²+(-3-x)²

10²=(8)²+(-3-x)²

100 = 64 + (-3-x)²

100-64 = (-3-x)²

36 = (-3-x)²

√36 = -3-x

6 = -3-x

6+3 = -x

9 = -x

-9 = x

Y ordinate is -9