Question

find the co-ordinates of point & which divides segment AB externally in the ratio coordinates of A=(0,10), B = (3,7) 2:5. ​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given :-

The points = A(0,10) and B (3,7)

The ratio = 2:5

To find :-

Find the co-ordinates of point which divides segment AB externally in the ratio 2:5 ?

Solution :-

Given points are A(0,10) and B (3,7)

Let (x1, y1) = A(0,10) => x1 = 0 and y1 = 10

Let (x2, y2) = B(3,7) => x2 = 3 and y2 = 7

Given ratio = 2:5

Let m1:m2 = 2:5 => m1 = 2 and m2 = 5

We know that

The co-ordinates of point P(x,y) which divides the linesegment joining (x1, y1) and (x2, y2) is

( (m1x2-m2x1)/(m1-m2) ,

(m1y2-m2y1)/(m1-m2) )

On substituting these values in the above formula

=> ({(2)(3)-(5)(0)}/(2-5) , { (2)(7)-(5)(10)}/(2-5) )

=> ( {6-0)/-3 , (14-50)/-3)

=> ( 6/-3 -36/-3 )

=> ( -2 , 12 )

Answer:-

The required coordinates of the point is ( -2 , 12 )

Used formulae:-

Section formula :-

The co-ordinates of point P(x,y) which divides the linesegment joining (x1, y1) and (x2, y2) is

( (m1x2-m2x1)/(m1-m2) ,

(m1y2-m2y1)/(m1-m2) )