Find the co-ordinates of point on x-axis which are at distance of 17 units from the point (11 - 8)
Lesson : Distance formula
Formula : √(x2-x1)²+(y2-y1)²
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Answer:
Let the coordinates of point on x axis be (x,0 )
According to the question,
17=√(11-x)²+(-8-0)²
17=√121+x²-22x + 64
Squaring both sides, we get-
289=185+x²-22x
After factorization we will get answer
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