Question

Find the co-ordinates of point which divides the line joining the point ( -4,7)&(4,-3) in the ratio 2:3 I NEED WITH STEPS. I NEED CORRECT ANSWER . WRONG ANSWER WILL BE REPORT

Answer 1

Step-by-step explanation:

I hope you will understand my explanation

Answer 2

Answer:

(-4/5 , 3)

Step-by-step explanation:

Hii Mate ^_^

We have to just apply Section Formula here.

Section Formula -

When a point divides a line joining the points (x₁,y₁) and (x₂,y₂) in the ratio m:n, then, the coordinates of that point will be,

{ [(mx₂+nx₁)/(m+n)] , [(my₂+ny₁)/(m+n)] }

So, here,

Let A(-4,7) , B(4,-3)

So, x₁= -4 , x₂=4

     y₁=7 , y₂= -3

So line is AB.

Ratio = m:n = 2:3

So, m=2 , n=3

Let C(a,b) be the point which divides AB in ratio 2:3

So, a = (mx₂+nx₁)/(m+n)

     b = (my₂+ny₁)/(m+n)

Applying Section Rule , we get

a = [2×4 + 3×(-4)] / (2+3)

  = (8-12) / 5

  = -4/5

b = [2×(-3) + 3×7] / (2+3)

  = (-6+21) / 5

  = 15/5

  = 3

Hence,

Required Point = C(a,b) = C (-4/5 , 3)

HOPE IT HELPS,

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