Question

* Find the co-ordinates of points on the x-axis which are at a distance of 17 units from the point (118) Olio Find the co-ordinates of the noin 19. Giver​

Answer 1

Let the required point be (x,0).

(x−11)

2

+(8)

2

=17

(x−11)

2

+64=289

x

2

+121−22x+64=289

x

2

−22x−104=0

x

2

−26x+4x−104=0

x(x−26)+4(x−26)=0

(x−26)(x+4)=0

x=26,−4

Hence, the required points are (26,0) and (−4,0).

Answer 2

Answer:

Let the required point be (x,0).

Let the required point be (x,0).(x−11)

Let the required point be (x,0).(x−11) 2

Let the required point be (x,0).(x−11) 2 +(8)

Let the required point be (x,0).(x−11) 2 +(8) 2

Let the required point be (x,0).(x−11) 2 +(8) 2

Let the required point be (x,0).(x−11) 2 +(8) 2

Let the required point be (x,0).(x−11) 2 +(8) 2 =17

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11)

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289x

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289x 2

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289x 2 +121−22x+64=289

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289x 2 +121−22x+64=289x

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289x 2 +121−22x+64=289x 2

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289x 2 +121−22x+64=289x 2 −22x−104=0

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289x 2 +121−22x+64=289x 2 −22x−104=0x

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289x 2 +121−22x+64=289x 2 −22x−104=0x 2

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289x 2 +121−22x+64=289x 2 −22x−104=0x 2 −26x+4x−104=0

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289x 2 +121−22x+64=289x 2 −22x−104=0x 2 −26x+4x−104=0x(x−26)+4(x−26)=0

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289x 2 +121−22x+64=289x 2 −22x−104=0x 2 −26x+4x−104=0x(x−26)+4(x−26)=0(x−26)(x+4)=0

Let the required point be (x,0).(x−11) 2 +(8) 2 =17(x−11) 2 +64=289x 2 +121−22x+64=289x 2 −22x−104=0x 2 −26x+4x−104=0x(x−26)+4(x−26)=0(x−26)(x+4)=0x=26,−4

Step-by-step explanation:

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