Question

Find the co-ordinates of the point of intersection of the medians of the triangle whose vertices
are A(-7, 5), B(-1, -3) and C(5, 7).
[Hint. Find the centroid of AABC.]
​

Answer 1

Answer:

For any triangle ABC, the true statement is:

A) AC2=AB2+BC2

B) AC=AB+BC

C) AC>AB+BC

D) AC<AB+BC

Answer

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Hint:

Here we will first draw the diagram of the triangle. Then we will form the condition from the basic property of the sides of the triangle and then select the required condition according to the given option.

Complete step by step solution:

First, we will draw a triangle ABC to get the correct relationship of the sides of the triangle.

We know this property of the triangle that the sum of any two sides of the triangle is always greater than the third side of the triangle.

So we can write the above property as

AB+BC>ACAB+AC>BCBC+AC>AB

So from the above formed conditions we have the first condition given as an option. So the required condition is

AB+BC>AC

We can write it as

AC<AB+BC

Hence, the true statement is AC<AB+BC

.

So, option D is the correct option