Find the co-ordinates of the point of intersection of the median of the triangle whose Celtics are A(-7,5),B(-1,-3) and C(5,7).
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POINT OF CONCURRENCE OF MEDIANS(CENTROID),
G = [(x1+x2+x³)/3],[(y1+y2+y³)/3]
THEREFORE, CENTROID OF ∆ABC,
G = [(-7-1+5)/3],[(5-3+7)/3]
G = [(-3)/3],[9/3]
G = (-1,3)
The medians of ∆ABC will intersect at point (-1,3)
G = [(x1+x2+x³)/3],[(y1+y2+y³)/3]
THEREFORE, CENTROID OF ∆ABC,
G = [(-7-1+5)/3],[(5-3+7)/3]
G = [(-3)/3],[9/3]
G = (-1,3)
The medians of ∆ABC will intersect at point (-1,3)
Hiteshbehera74:
my method is lengthy to understand it better
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G(-7-1+5÷3),(5-3+7÷3)
G(-8+5÷3),(-3+12÷3)
G(-3/3,9/3)
G(-1,3)
G(-8+5÷3),(-3+12÷3)
G(-3/3,9/3)
G(-1,3)
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