find the co ordinates of the point on x axis which are at yhe distance of 10 units from (3 6)
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Step-by-step explanation:
Let the points on x-axis be P(x,0) and Q(y,0) which are at distance of 10 units from point A(11,−8)
Which implies:
PA=QA
or PA2=QA2
(11−x1)2+(−8)2=(11−x2)2+(−8)2=102
(11−x)2+(−8)2=102
121=22x+x2+64=100
x2−22x+85=0
x2−12x−5x+85=0
x(x−17)−5(x−17)=0
(x−17)(x−5)=0
Either (x−17)=0 or (x−5)=0
x=17 or x=5
So, the points are: (17,0) and (5,0).
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