Find the co-ordinates of the point on Y-axis which is equidistant from S (-3, -1) & T (2, -2)
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Step-by-step explanation:
(x1+x2/2'y1+y2/2)
(-3+2/2,-1-2/2)
from y co ordinates=(0,y)
:-1/2=0,-3/2=y
::y=-3/2
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