Question

find the co-ordinates of the point thag divides the line segment joining the points P(5,-2) and Q(9,6) internally in the ratio 3:1.

Answer 1

$\huge \mathfrak {Answer:-}$

By using Section formula,

We get,

$x = \frac{m1x2 + m2x1}{m1 + m2}$

$x = \frac{3 \times 9 + 1 \times 5}{3 + 1} = \frac{32}{4} = 8$

$y = \frac{m1y2 + m2y1}{m1 + m2}$

$y = \frac{3 \times 6 + 1 \times - 2}{3 + 1} = \frac{16}{4}= 4$

Therefore,

The co-ordinates are $(8, 4)$

$\huge {Be\:Brainly}$❤️

Answer 2

$\bold{\huge{Hay!!}}$


$\bold{Dear\:user!!}$


$\bold{\underline{Question-}}$


find the co-ordinates of the point thag divides the line segment joining the points P(5,-2) and Q(9,6) internally in the ratio 3:1. ?



$\bold{\underline{Answer-}}$According to the question we know that the points are
P, Q

Given, x1 = 5, y1 = -2

$\:\:\:\:\:\:\:\:\:\:\:$ x2 = 9 , y2 = 6

or m1 : m2 = 3 : 1

Now, using the section formula


$x = \frac{m1x2 + m2x1}{m1m2}$

x = (3*9 + 1*5) /( 3 + 1 )

x = 32 / 4

x = 8



$y = \frac{m1y2 + m2y1}{m1m2}$


y = {3*6+1*(-2)} / (3+1)

y = 16 / 4

y = 4

Now, The co-ordinates of the point is ( 8, 4 )