Find the co-ordinates of the point which divides the line segment joining the points (1. -3) and (3.9) in the ratio 1:3 internally.
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Answer:
Using the section formula, if a point (x,y) divides the line joining the
points (x
1
,y
1
) and (x
2
,y
2
) in the
ratio m:n, then (x,y)≡(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
Substituting (x
1
,y
1
)=(1,−3) and (x
2
,y
2
)=(−3,9) and m=1,n=3 in the section formula, we get
the point (
1+3
1(−3)+3(1)
,
1+3
1(9)+3(−3)
)=(0,0)
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