Question

Find the co-ordinates of the points of trisection of the line joining the points (3,-1) and (0, 2).​

Answer 1

Answer:

P(2,0) and Q(1,1) are point of trisection.

Step-by-step explanation:

A(3,-1) B(0,2)

Let A(3,-1) be the first point and B(0,2) be the second point and P and Q be the internally trisecting point

Let AB=PQ=QB=K

PB=PQ+OB=2K

And AQ=AP+PQ=2K

AP=PB=1:2

And AQ:QB=2:1

P divides a,b internally in ratio 1:2 while

Q divides internally in the ratio 2:1 does coordinates of p and q are

P(1(0)+2×(3)/1+2 , 1(2)+2(-1)/1+2)= P(2,0)

Q(2(0)+1×(3)/1+2 , 2(2)+1(-1)/1+2)= Q(1,1)

P(2,0) and Q(1,1) are point of trisection.

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