Question

Find the co-ordinates of the points of trisections of the line segement joining the points (3-1)and (6,8)​

Answer 1

Answer:

I can try....

Step-by-step explanation:

here if we trisect the line, we have

let A(3,-1) and B(6,8) and p and q are the points on the line segment AB which trisects it. understand?

now if line trisect then it has 3 equally parts.

so for P point we have ratio 1:2 and for Q point ratio is2:1.

because line has 3 equally parts.

now, using section formula, we have,,,

x=(m1)(x2)+(m2)(x1)/m1+m2

x=(1)(6)+(2)(3)/3

x=6+6/3

x=12/3=4

x=4.....

now,,

y=(m1)(y2)+(m2)(y1)/m1+m2/

y=(1)(8)+(2)(-1)/3

y=8-2/3,,, y=6/3=2....

y=2.........

these are coordinates for point P.

now for Q point we have, I write shortly? ok...

x=(2)(6)+(1)(3)/3

x=12+3/3,,,,, x=15/3=5,,....

x=5......

now for y, we have

y=(2)(8)+(1)(-1)/3

y=16-1/3,,,, y=15/3=5

y=5,,,,,

these are coordinates for point Q.

hence,

P=(4, 2)

Q=(5, 5)

I hope it's helpful for you,,,......

thank you.....