Question

find the co-ordinates of the points on y axis which are at the distance of 10 units from the point (6,6)​

Answer 1

Answer:

$\huge \green{y = 14 \: \: or \: \: - 2}$

Step-by-step explanation:

Let the required point be ( 0 , y ) . Note that x coordinate will be zero because point lies on y axis. Now this point is at distance 10 from ( 6 ,6 )

, so use distance formula

$\sqrt{(0 - 6) {}^{2} + (y - 6) {}^{2} } = 10 \\ \\ \implies 36 + (y - 6) {}^{2} = 100 \\ \\ \implies (y - 6) {}^{2} = 100 - 36 = 64 \\ \\ \implies y - 6 = \sqrt{64} = \pm8 \\ \\ y = 6 + 8 \: \: or\: \: 6 - 8 \\ \\ y = 14 \: \: \: or \: \: - 2$

Answer 2

Answer:

Step-by-step explanation

topic :

• coordinates

given :

• find the co-ordinates of the points on y axis which are at the distance of 10 units from the point (6,6)

to find :

• the distance of 10 units from the point (6,6)

solution :

• On the y axis, X=0. So the point will be of the form X-0 or (0,y)

• Now from (6,6) to the y axis, using the distance formula which is

• √(x-x)² + (Y-y)² = D

• (Where X and Y are the points on the X and Y axis, and x and y are the coordinates of the other points and D is the distance)

• please check the attached file I have fully explain you

answer :

• 10 units from the point (6,6) = y= 14