find the co-ordinates of the points on y axis which are at the distance of 10 units from the point (6,6)
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Let the required point be ( 0 , y ) . Note that x coordinate will be zero because point lies on y axis. Now this point is at distance 10 from ( 6 ,6 )
, so use distance formula
[tex]\begin{gathered} \sqrt{(0 - 6) {}^{2} + (y - 6) {}^{2} } = 10 \\ \\ \implies 36 + (y - 6) {}^{2} = 100 \\ \\ \implies (y - 6) {}^{2} = 100 - 36 = 64 \\ \\ \implies y - 6 = \sqrt{64} = \pm8 \\ \\ y = 6 + 8 \: \: or\: \: 6 - 8 \\ \\ y = 14 \: \: \: or \: \: - 2\end{gathered}
(0−6)
2
+(y−6)
2
=10[tex]
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