Find the co-ordinates of vertex of the parabola whose focus is (0,0) and the directrix is the line 2x +y=1
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ANSWER
Focus(0,0)
eq
n
of directrix = 2x−y−1=0
Let A(x,y) be the pt. on the parabola
and AM be the length of the perpendicular
from A to the directrix.
Then,
SA = AM
⇒(SA)
2
=(AM)
2
⇒(x−0)
2
+(y−0)
2
=(
2
2
+(−1)
2
2x−y−1
)
2
⇒x
2
+y
2
=
5
(2x−y−1)
2
⇒5x
2
+5y
2
=4x
2
+y
2
−4xy+1+4x−2y
⇒x
2
+4y
2
+4xy−4x+2y−1=0
Which is the required eq
n
of parabola.
Step-by-step explanation:
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