Question

find the co ordinator of the point which divides the join of (4,-3) & (8,3) in the ratio of 3:1​

Answer 1

Answer:

The point of (x,y) coordinates are (7,3/2)

Step-by-step explanation:

x1 = 4

x2 = 8

y1 = -3

y2 = 3

m = 3

n = 1

x = mx2 + nx1/m+n

= 3*8 + 1*4/3+1

= 24 + 4/ 4

= 28/4

= 7

y = my2 + ny1/ m+n

= 3*3 + 1*-3/3+1

= 9-3/4

= 6/4

= 3/2

Answer 2

Answer:

so .coordinate are = x= 77/11

and y= 15/11

Step-by-step explanation:

let A = (4 ,- 3) B =(8,3 )

Ratio is 8:3

and let coordinate of point p = (x,y)

so, by section formula we get,

x = m1x2+ m2x1 /m1 +m2

y = m1y2+m2y1/m1+ m2

on putting we get ,

x = 8(8)+ 3(4) / 11 y = 8(3) + 3(-3)/11

x = 12 + 64/11 y = -9 + 24 /11

× = 76/11 y = 15/11

× = 77/6