find the co-ordinator of vertices of a triangle sides of mid points at (2,1),(-1,3)and(-2,5)
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Answer:The vertices of triangle is
A(1,3) B(3,-1)andC(-5,7)
Step-by-step explanation:
Let the vertices be A(x1,y1),B(x2,y2)and C(x3,y3)
The mid point of AB(2,1)BC(-1,3)andAC(-2,5)
Then
x1+x2=4,y1+y2=2
x2+x3=-2,y3+y2=6
x1+x3=-4,y1+y3=10
Then solve the the eqn
x1 =1,x2=3,x3=-5andy1=3,y2=-1,y3=7
Then A(1,3) B(3,-1)andC(-5,7)
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