find the co prdinates of points jouning (4,7) and (-2,-3) in the ratio 1:2
Answers
Step-by-step explanation:
Given:-
The points = (4,7) and (-2,-3)
The ratio 1:2
To find:-
Find the co ordinates of point which divides the linesegment joining the points (4,7) and (-2,-3) in the ratio 1:2?
Solution:-
Given points are (4,7) and (-2,-3)
Let (x1, y1)=(4,7)=>x1=4 and y1=7
Let (x2, y2)=(-2,-3)=>x2=-2 and y2=-3
Given ratio = 1:2
Let m1:m2 = 1:2=>m1=1 and m2=2
We know that
The coordinates of a point P(x,y) which divides the line segment joining the points A(x1, y1) and B(x2, y2) in the ratio m1:m2 internally is
( {m1x2+m2x1}/(m1+m2) , {m1y2+m2y1}/(m1+m2) )
On Substituting values in the formula then we get
=> p(x,y)
=> ( {(1)(-2)+(2)(4)}/(1+2) , {(1)(-3)+(2)(7)}/(1+2) )
=> ( {-2+8}/3 , {-3+14}/3 )
=> ( 6/3 , 11/3 )
=> ( 2 , 11/3 )
P(x,y) = (2,11/3)
Answer:-
The required coordinates of the point = (2,11/3)
Used formula:-
The coordinates of a point P(x,y) which divides the line segment joining the points A(x1, y1) and B(x2, y2) in the ratio m1:m2 internally is
( {m1x2+m2x1}/(m1+m2) , {m1y2+m2y1}/(m1+m2) )
Answer:
2,11/3 us your answer
Step-by-step explanation:
Don't mind the handwriting
