Math, asked by Ansa3890, 1 year ago

find the coefficent of x^2 in(2-3x^2)(x^2-5)​

Answers

Answered by Kanishka7228
0

Answer:

2( {x}^{2}  - 5) - 3 {x}^{2} ( {x}^{2} - 5) \\ 2 {x}^{2}   - 10 - 3 {x}^{4}   + 15 {x}^{2}  \\ 17 {x}^{2}  - 10 - 3 {x}^{4}

hence coefficient of x^2 is 17

Answered by guptakartike25af
0

Answer:

The coefficient of x^2 is 17.

Step-by-step explanation:

  =     (2-3x^2) (x^2-5)​

  =     2(x^2-5) -3x^2(x^2-5)​

  =     2x^2-10-3x^4+15x^2

  =     17x^2-10-3x^4

          coefficient of x^2 is 17

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