Question

Find the coefficient of p in the expansion of (5 − p
)
^
2​

Answer 1

Answer:

-1

Step-by-step explanation:

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Answer 2

Answer:

In the expansion of (x

2+

x

1

)

2n

we have

t

r+1

=2nC

r

.(x

2

)

2n−r

.

x

r

1

=2nC

r

.(x)

4n−2r

.

x

r

1

=2nC

r

.(x)

4n−3r

Putting (4n−3r)=p we get r=

3

1

(4n−p)

Coefficient of x

p

=2nC

(

3

1

)(4n−p)

=

[

3

1

(4n−p)!]∗[2n−

3

1

(4n−p)]!

2n!

=

[

3

(4n−p)

]∗[

3

(2n+p)

]!

2n!