Find the coefficient of in the expansion of
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not sure tried to do the problem
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Solution:-
Refer to the Attachment!!
Method of Solution:-
Step 1:
Just sent the ( 1+x)³ from Denominator to Numerator.
( 2 + x + x²)/(1+x)³
=> ( 2+x+x²)(1+x)^(-3).
Then,
Taken 1/2 common.
1/2[ 2 (x+1)(x+2)+x(x+1)+(x-1)x]
=> 2(-1)ⁿ/2 [ x² + 2x + x +2+2x² + 2x + 2x² -2x²]
After Cancelling we get,
=> (-1)ⁿ[ 5x² + 3x + 2]
Hence,
(-1)ⁿ[ 5x² + 3x + 2] is the Answer.
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