Chemistry, asked by razhiyamenon, 10 months ago

find the coefficient of volume expansion for an ideal gas at constant pressure​

Answers

Answered by Anonymous
7

Answer:

Coefficient of volume expansion:

\implies  \rm \dfrac{\Delta V}{V}  =  \gamma \Delta \theta \\

\implies  \rm   \gamma  = \dfrac{\Delta V}{ V\Delta \theta} \\

\implies  \purple{ \rm   \gamma  =  \dfrac{1}{v} . \dfrac{dv}{dT}  \:  \: ....(i)}\\

By ideal gas equation:

 \implies PV = nRT

Taking derivative on both sides w.r.t to T:

\implies  \dfrac{d}{dT} (PV) = \dfrac{d}{dT}(nRT)

\implies  P.\dfrac{dV}{dT} = nR

\implies \red{ \rm  \dfrac{dV}{dT} =  \dfrac{nR}{P} \:  \:  \: ...(ii)}

Substituting the value of dV/dT from equation (ii) to equation (i) :

\implies    \gamma  =  \dfrac{1}{v} . \dfrac{nR}{P}  \\

\implies    \gamma  =  \dfrac{nR}{PV}  \\

\implies    \gamma  =  \dfrac{nR}{nRT}  \\

\implies   \underline{ \boxed{ \orange{ \bf  \gamma  =  \dfrac{1}{T}  }}}

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