find the coefficient of x^98 in the product (x-1)(x-2)(x-3)..........(x-100)
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The coefficient of
x^98 in
(x-1)(x-2)(x-3)(x-4)..................(x-100)
will be 1`*2+2*3+3*4+4*5+.................+ n(n+1)`
`sum[n(n+1)]` where n=1 to n=100
```sum(n^2+n)` = `sum n^2 +sum n` = n(n+1)(2n+1)/6 + n(n+1)/2 now put n=100 then u will get 174225
so the final answer will be 174225
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hey ur answer is in attachment pic .
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