find the coefficient of x in expansion (x+3)^3
Answers
Answered by
2
Answer:
27
Step-by-step explanation
(x²+6x + 9)(x+3)
x³+6x² + 9x +3x² +18x +27
x³ + 9x²+27x +27
Answered by
4
Answer : Coefficient of x is 27
Explanation :
(x + 3)³
= x³ + 3³ + 3.x.3(x +3)
= x³ + 27 + 9x(x + 3)
= x³ + 27 + 9x² + 27x
= x³ + 9x² + 27x + 27
Therefore from the above polynomial :
coefficient of x³ = 1
coefficient of x² = 9
coefficient of x = 27
constant = 27
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