Math, asked by rishabh337, 1 year ago

find the coefficient of x in expansion (x+3)^3​

Answers

Answered by Natrulz257
2

Answer:

27

Step-by-step explanation

(x²+6x + 9)(x+3)

x³+6x² + 9x +3x² +18x +27

x³ + 9x²+27x +27

Answered by Anonymous
4

Answer : Coefficient of x is 27

Explanation :

(x + 3)³

= x³ + 3³ + 3.x.3(x +3)

= x³ + 27 + 9x(x + 3)

= x³ + 27 + 9x² + 27x

= x³ + 9x² + 27x + 27

Therefore from the above polynomial :

coefficient of x³ = 1

coefficient of x² = 9

coefficient of x = 27

constant = 27

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