find the coefficient of x in the expansion of (x+2)³ with explanation
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Solution➜
☞Given: We have to expand (x+2)³.
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Formula used: (a+b)³=a³- 3a²b + 3ab² - b³
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Let's find
(x+2)³=x³-3x²2+3x2²-2²
=3 and 4 and 2 are Coefficients.
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Hence According to the question the Coefficients in the given number is 3,4 and 2
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More basic identities➜
☞(a+b)²=a²+2ab+b²
☞(a-b)²=a²-2ab+b²
☞(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
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Answer::
Coefficient is 4 , 3 and 2.
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