Question

find the coefficient of X in the expansion of (X+3)whole cube
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Answer 1

Answer:

coefficient of x is 27

Step-by-step explanation:

(x+3)³

x³+3³+3*x²*3+3*x*3²

x³27+9x²+27x

coefficient of x is 27

Answer 2

Answer:

The coefficient of x in the expansion of $(x+3)^3$ is 27.

Step-by-step explanation:

Given : Expansion of $(x+3)^3$

To find : The coefficient of x in the expansion?

Solution :

First we expand the expression,

$(x+3)^3=x^3+3^3+3(x)^2(3)+3(x)(3)^2$

$(x+3)^3=x^3+27+9x^2+27x$

$(x+3)^3=x^3+9x^2+27x+27$

The coefficient of x is 27.

Therefore, The coefficient of x in the expansion of $(x+3)^3$ is 27.