find the coefficient of x square in [3x+xcube] [x+1/x]
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8
There will be no term which will contain x so the co-efficient of x will be zero
expanding the equation we get
4x² + x⁴ + 3 = 4x² + x⁴ + 3 + 0.x so the coefficient of x is 0
expanding the equation we get
4x² + x⁴ + 3 = 4x² + x⁴ + 3 + 0.x so the coefficient of x is 0
trogenspfere78:
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Answered by
7
coefficient of x square is (3+1=) 4.
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