find the coefficient of x2 and x in the product of (x-3) (x+7) (x-4)
Answers
Answer:
0
-37
Step-by-step explanation:
find the coefficient of x2 and x in the product of (x-3) (x+7) (x-4)
Method 1 :
(x-3) (x+7) (x-4)
= (x+7) (x-3)(x-4)
= ( x + 7) (x² - 7x + 12)
= x³ - 7x² + 12x + 7x² - 49x + 84
= x³ - 37x + 84
Coefficient of x² = 0 & x = -37
Method 2 :
(x-3) (x+7) (x-4)
roots are 3 , 4 & - 7
Sum of roots = Coefficients of x²/Coefficient of x³
=> 3 + 4 - 7 = Coefficients of x²/1
=> Coefficients of x² = 0
3*4 + 4*(-7) + 3(-7) = Coefficients of x/Coefficient of x³
=> 12 - 28 - 21 = Coefficients of x/1
=> Coefficients of x = -37
Answer:
0;-37
Step-by-step explanation:
find the coefficient of x^2 and x in the product of (x-3) (x+7) (x-4)
(x-3) (x+7) (x-4)
= (x+7) (x-3)(x-4)
= ( x + 7) (x² - 7x + 12)
= x³ - 7x² + 12x + 7x² - 49x + 84
= x³ - 37x + 84
Coefficient of x² = 0 & x = -37