find the coefficient of x2 and x in the product of (x-5) (x+3) (x+7)
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(x-5)(x+3)(x+7) = (x^2 + (3-5)x + -5*3) (x+7)
(x^2 -2x -15) (x+7) = (x^3 -2x^2 -15x) + (7x^2 -14x -105) = x^3 +5x^2 - 29x - 105
So the coefficient of x^2 = 5 and x = - 29
(x^2 -2x -15) (x+7) = (x^3 -2x^2 -15x) + (7x^2 -14x -105) = x^3 +5x^2 - 29x - 105
So the coefficient of x^2 = 5 and x = - 29
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