Find the coefficient of x³ in the expansion p (x) = (3x - 4) (x² + 5x - 1)
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Answered by
0
Answer:
3
Step-by-step explanation:
hope it helps you. ans is 3
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Answered by
10
Answer:
3
Step-by-step explanation:
p(x) = (3x - 4) (x² + 5x - 1)
p(x) = 3x ( x² + 5x - 1) - 4(x²+5x -1)
p(x) = 3x³ +15x² - 3x -4x² - 20x -4
p(x) = 3x² - 15x² -4x² -20x -3x -4
p(x) = 3x³ - 19x² - 23x -4
So, the cofficient of x³ is 3....
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