Math, asked by Shahnawaz9447, 8 months ago

Find the coefficient of x³ in the expansion p (x) = (3x - 4) (x² + 5x - 1)

Answers

Answered by paramjitkanwalkaur
0

Answer:

3

Step-by-step explanation:

hope it helps you. ans is 3

Attachments:
Answered by Anonymous
10

Answer:

3

Step-by-step explanation:

p(x) = (3x - 4) (x² + 5x - 1)

p(x) = 3x ( x² + 5x - 1) - 4(x²+5x -1)

p(x) = 3x³ +15x² - 3x -4x² - 20x -4

p(x) = 3x² - 15x² -4x² -20x -3x -4

p(x) = 3x³ - 19x² - 23x -4

So, the cofficient of x³ is 3....

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