Question

Find the coefficient of x9y3 in the expression of (2x-3y)12

Answer 1

The general term in a given expansion
${(a \: + b) }^{n}$
is given by,
$t_{r + 1} = \: \binom{n}{r} {a}^{n - r}. {b}^{r}$
According to question,
a = 2x
b = -3y
n = 12.

To determine the coefficient of
${x}^{9} {y}^{3}$
Put r = 3,
$t_{4} = \binom{12}{3} {(2x)}^{9} .{ (-3y)}^{3}$
Therefore, coefficient of
${x}^{9} {y}^{3}$
is 3041280.

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Answer 2

Answer:

4555885855855458680768880;-'';;-'(! vggduyfjh

3

Explanation:

3586886858855888888888888888