Math, asked by skf66106, 16 days ago

Find the coefficients of x¹⁵ in the expansion of (x³+2/x²)¹⁰​

Answers

Answered by jemimanayak
3

Answer:

(x³+2/x²)¹⁰

=((x³)¹⁰ + (2/x²))¹⁰

=((x³⁰) + (2¹⁰/x²⁰))

=(x³⁰+ 1024/x²⁰)

So the coefficient of x¹⁵ = (x¹⁵ + 1024/x⁵)

Similar questions