Find the coefficients of x¹⁵ in the expansion of (x³+2/x²)¹⁰
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Answer:
(x³+2/x²)¹⁰
=((x³)¹⁰ + (2/x²))¹⁰
=((x³⁰) + (2¹⁰/x²⁰))
=(x³⁰+ 1024/x²⁰)
So the coefficient of x¹⁵ = (x¹⁵ + 1024/x⁵)
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