Question

find the coffiecient of x^2 and x in the expansions (x-3) (x+7) (x-8)​

Answer 1

hope this is helpful for you

Answer 2

$= (x - 3)(x + 7) (x - 8) \\ = ( {x}^{2} + 7x - 3x - 21)(x - 8) \\ = ( {x}^{2} + 4x - 21)(x - 8) \\ = {x}^{3} - 8 {x}^{2} + 4 {x}^{2} - 32x - 21x + 168 \\ = {x}^{3} - 4 {x}^{2} - 53x + 168$

Therefore,

$coffiecient \: of \: {x}^{2} = - 4 \\ and \\ coffiecient \: of \: x = - 53$

hope it will help u ✨☺️