Question

find the coffiecient of x^2 and x in the expansions (x-3) (x+7) (x-8)

explain it step by step
Explain it step by step
Explain it step by step​

Answer 1

Answer:

(x-3) (x+7) (x-8) = 0 (given expansion)

(x^2+7x-3x-21) (x-8)=0 (distributive property applied

for (x-3) and (x+7))

x^3-8x^2+7x^2-56x-3x^2+24x-21x+168=0

(distributive property for the

rest)

x^3-4x^2-53x+168=0

coeffecient of x^2 = -4

coeffiefient of x = -53