Find the coffiecient x^2in (2x^2-5)(4+3x^2)
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By the Binomial Theorem, [2x-(1/2x)]^6 can be expanded to the sum as k goes from zero to 6 of (6 choose k)×(2x)k×(-1/2x)6-k. The only time we will be left with an x2 term is when k=4, since we'll have some coefficient multiplied by x4/x2. So, we'll have (6 choose 4) × (2x)4×(-1/2x)2, which is 15×16x4×(1/4x2)= 60x2.
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