Question

find the combined equations of lines passing through
Origin
perpendicular of is parallel to at
x+2y=5
and other is perpendicular
2x-y+3=0​

Answer 1

Step-by-step explanation:

The line parallel to the line x−2y=2 is x−2y=k which passes through (3,2) then we get, 3−2.2=k or, k=−1.

So the equation of the line is x−2y=−1.....(1)

Again the line perpendicular to y=3 is x=k, which passes through (3,2) then we've, x=3.....(2)

Now joint equation represented by (1) and (2) is,

(x−3)(x−2y+1)=0.

Answer 2

Answer:

it is night or all the stars are shining