Find the combined pH of the mixture.
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Example #1: Calculate the pH of a solution obtained by mixing 100. mL of an acid of pH = 3.00 and 400. mL solution of pH = 1.00.
Solution:
1) Determine total moles of H+ in solution:
for pH = 3.00, [H+] = 0.0010 M
for pH = 1.00, [H+] = 0.10 M
(0.0010 mol/L) (0.100 L) = 0.00010 mol
(0.10 mol/L) (0.400 L) = 0.040 mol
0.040 mol + 0.00010 mol = 0.0401 mol
Note: we ignore the H+ contribution from water.
2) Determine the [H+] of the combined solution:
0.0401 mol / 0.500 L = 0.0802 M
3) Determine the new pH:
pH = −log 0.0802 = 1.096
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