find the common difference and 20 th term of arithmetic progression 6,12,18......
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Solution:
Since a= 6
common difference d= 12-6 = 6
20 th term
Tn = a+(n-1) d
T20 = a+(20-1)6
T20 = 6+19(6)
T20 = 6+114
T20= 120
Common difference = 6, 20 th term = 120
Solution:
Since a= 6
common difference d= 12-6 = 6
20 th term
Tn = a+(n-1) d
T20 = a+(20-1)6
T20 = 6+19(6)
T20 = 6+114
T20= 120
Common difference = 6, 20 th term = 120
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