find the common difference and sum of 51 terms of an ap 1,3,5,7,....
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Answer: common difference=2; sum=102
Step-by-step explanation:
The common difference of an AP is the difference of two consecutive terms
3-1=5-3=7-5=common difference =2
The sum of “n” terms of an AP formula:
2a+(n-1)d [a= 1st term; n=number of terms; d=common difference]
Here the sum of the given AP is 2(1)+(51-1)2= 2+(50*2)= 2+100= 102
Hope this helps
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