find the common difference in Q.2
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b2kryadavptkt:
-2
Subtract 1/3q from 1-6q/3q
a series is said to be in arithmetic progression if the common difference is same through out the series
difference between 1st term and 2nd term should be equal to difference between 2nd term and 3rd term ie. c. d = a2 - a1 = a3 - a2
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Answer:
this is not in Arithmatic Progression
Step-by-step explanation:
Answered by
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Answer: 1/3$,1-6$/3$
=1-6$/3$-1/3$
=1-6$-1/3
=-6$/3$
=-2
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