Find the common difference of an A.P 1/2b , 1−6/2b , 1−12/2b
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Answer:
Step-by-step explanation:
a=t1= 1/2b
t2 = -5/2b t3 = -11/2b
Common Difference (d1) = t2 - t1
-5/2b-1/2b = -5-1/2b = -6/2b
Common difference (d2) = t3-t2
-11/2b-(-5/2b) = -11/2b + 5/2b = -11+5/2b =-6/2b
d1 = d2
hence d = -6/2b
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