Question

Find the common difference of an A.P I n which a16-a12=16

Answer 1

that is correct answer for your question

Answer 2

Answer:

4

Step-by-step explanation:

The nth term of A.P. = $a_n=a+(n-1)d$   ---A

We are given that $a_{16}-a_{12}=16$

Substitute n = 16 in A

$a_{16}=a+(16-1)d$

$a_{16}=a+15d$

Substitute n = 12 in A

$a_{12}=a+(12-1)d$

$a_{12}=a+11d$

Now,  $a_{16}-a_{12}=16$

$a+15d-(a+11d)=16$

$a+15d-a-11d=16$

$4d=16$

$d=\frac{16}{4}$

$d=4$

Hence the common difference of given A.P. is 4