Question

find the common difference of an A.P. if its nth term is given by an = 10/3n + 5

Answer 1

n=1 10/3*1+5 = 3.3+5=8.5 n=2 10/3*2+5 =5/3+2 = 1.6+5=7.5 d=7.5-8.5=-1

Answer 2

we are given

an=10/3n+5

we have to find difference of a.p

as we know that distance of a.p

d=an+1-an

in other words difference can b

d=a2-a1

find a1 and a2 by replacing n by 1 and 2 respectively in the given equation

a1=(10/3*1)+5=10/3+5=25/3

a2=(10/3*2)+5=10/6+5=40/6

d=a2-a1=40/6-25/3

d=(40-50)/6

d= -10/6

d=-5/3