Question

find the common difference of an A.P whose 26th term is 160 and first term is 10.​

Answer 1

Answer:

Here is your answer mate

Step-by-step explanation:

QUESTION,

find the common difference of an A.P whose 26th term is 160 and first term is 10.

Answer,

Formula,

• Nth term in Arithmetic progression is An = A + (n - 1) d

• Here, d is common difference
• A is 1st term
• An is nth term

Solution,

Give,

1st term = 10 = A

26th term = 160

Apply Formula,

26th term = 160 = A + (n - 1) d

$\: \: \: \: \: \: \: \: \: \: \: \:${26th term so n is 26}

$\: \: \: \: \: \: \:\: \: \: \: \:\: \: \: \: \: \: \:$= 10 + (26 - 1) × d

160 = 10 + 25 × d

160-10 = 25 × d

25 d = 150

d = 150/25

d = 6

So, common difference is 6

Have a good day ❤️

Answer 2

Answer:

QUESTION,

find the common difference of an A.P whose 26th term is 160 and first term is 10.

Answer,

Formula,

Nth term in Arithmetic progression is An = A + (n - 1) d

Here, d is common difference

A is 1st term

An is nth term

Solution,

Give,

1st term = 10 = A

26th term = 160

Apply Formula,

26th term = 160 = A + (n - 1) d

\: \: \: \: \: \: \: \: \: \: \: \: {26th term so n is 26}

\: \: \: \: \: \: \:\: \: \: \: \:\: \: \: \: \: \: \: = 10 + (26 - 1) × d

160 = 10 + 25 × d

160-10 = 25 × d

25 d = 150

d = 150/25

d = 6

So, common difference is 6