Question

Find the common difference of an A.P.whose first term is 5 and the sum of its first four terms is
half the sum of the next four terms.​

Answer 1

Answer:

Step-by-step explanation:

given first term=5

sum of first four terms=a+a+d+a+2d+a+3d

=20+6d

sum of next four terms=

a+4d+a+5d+a+6d+a+7d=

20+22d

therefore

20+6d=1/2(20+22d)

20+6d=10+11d

10=5d

d=10/5

d=2