Find the common difference of an A.P. whose first term is 5, and the number of terms is 30 and sum 1455.
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Step-by-step explanation:
first term a=5, last term l=45 and Sn = 400
Since, Sn=2n(a+l)
⇒400=2n(5+45)
⇒400=2n(50)
⇒400=n(25)
⇒n=16
Since, l=a+(n−1)d
⇒45=5+(16−1)d
⇒45−5=(15)d
⇒40=15d
⇒d=1540
⇒d=38
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